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Electromagnetic Induction Class 12 Physics Important Questions 2026–27

Electromagnetic Induction Class 12 Physics Important Questions 2026–27
Chapter 6 important questions with answers covering magnetic flux, Faraday's laws, Lenz's law, induced EMF, motional EMF, self-induction, mutual induction and exam-style numerical application.
Class 12 PhysicsChapter 6CBSE 2026–27Important QuestionsWith Answers
How this page is built: The question set is based on the current CBSE 2026–27 Chapter 6 scope and current assessment/search-intent research. The official curriculum places electromagnetic induction, Faraday's laws, induced EMF/current, Lenz's law, self-induction and mutual induction in Chapter 6. AC generator and transformer are kept with Chapter 7: Alternating Current.

Official CBSE Physics Curriculum 2026–27 · Official Class XII SQP & Marking Scheme

Important: These are original Learn Revise Hub practice questions, not predictions or official CBSE questions. The set deliberately mixes definition, reasoning, direction, numerical and higher-order questions. Current CBSE assessment design gives substantial weight to application and higher-order thinking, so students should practise explaining why an answer follows, not only memorising formulas.

1. Most Important Topics to Prepare

Magnetic Flux
Φ = BA cos θ, area-vector angle, maximum/zero flux and flux change.
Faraday's Laws
Induced EMF, rate of flux change, average and instantaneous forms.
Lenz's Law
Direction of induced current and conservation-of-energy reasoning.
Motional EMF
Moving conductor, ε = Bℓv and direction.
Self-Induction
L, ε = −L dI/dt, long-solenoid inductance and stored energy.
Mutual Induction
M, induced EMF in a second coil and coupled-solenoid relation.

2. High-Priority Concepts Before Practice

Induced charge
For a simple closed circuit of resistance R, the total induced charge for a flux change is obtained from q = N|ΔΦ|/R. This is useful when a question gives total flux change rather than the time taken.
Eddy currents — enrichment
Eddy currents are circulating currents induced in bulk conductors when magnetic flux through different parts changes. Learn the concept and common applications, but keep this separate from the explicitly named CBSE 2026–27 Chapter 6 core.
Research note: Current search results for Chapter 6 repeatedly emphasise Faraday's law, Lenz's law, motional EMF, self-induction and mutual induction. Some third-party pages also add AC generators and eddy-current applications. We keep the current CBSE chapter boundary clear rather than treating every NCERT/online addition as a compulsory board requirement.

3. Very Short Answer Questions — 1 Mark

Q1 · 1 Mark

What is electromagnetic induction?

Answer: It is the phenomenon of production of induced EMF in a circuit when the magnetic flux linked with the circuit changes.
Q2 · 1 Mark

Write the expression for magnetic flux through a plane surface in a uniform magnetic field.

Answer: ΦB = BA cos θ, where θ is the angle between B and the area vector.
Q3 · 1 Mark

What is the SI unit of magnetic flux?

Answer: Weber (Wb).
Q4 · 1 Mark

State Faraday's law for an N-turn coil.

Answer: ε = −N dΦB/dt.
Q5 · 1 Mark

What does the negative sign in Faraday's law signify?

Answer: It represents Lenz's law: the induced effect opposes the change in magnetic flux responsible for induction.
Q6 · 1 Mark

Can an induced EMF exist in an open circuit?

Answer: Yes. A changing flux can induce EMF, although an open circuit does not permit a sustained induced current.
Q7 · 1 Mark

What is the SI unit of self-inductance?

Answer: Henry (H).
Q8 · 1 Mark

Write the expression for the motional EMF of a rod of length ℓ moving with speed v perpendicular to a magnetic field B in the standard geometry.

Answer: ε = Bℓv.
Q9 · 1 Mark

What is mutual induction?

Answer: It is the induction of EMF in one coil due to a change of current in another magnetically coupled coil.
Q10 · 1 Mark

Write the energy stored in an inductor carrying current I.

Answer: U = ½LI².

4. Conceptual and Reasoning Questions — 2 Marks

Q11 · 2 Marks

A magnet is held stationary near a conducting coil. The galvanometer shows no sustained deflection. Explain why.

Answer: When the magnet and coil remain stationary, the magnetic flux linked with the coil remains constant. Therefore dΦB/dt = 0 and no sustained induced EMF is produced.
Q12 · 2 Marks

A magnet is moved towards a coil and then away from it. Why does the galvanometer deflection reverse?

Answer: The change in magnetic flux reverses when the direction of relative motion is reversed. By Lenz's law, the induced EMF/current therefore reverses direction.
Q13 · 2 Marks

Why is the angle in Φ = BA cos θ measured between the magnetic field and the area vector rather than the plane of the coil?

Answer: Flux is the dot product B·A. The area vector is perpendicular to the surface, so θ is defined between B and this normal vector. If the angle with the plane is given, the complementary angle must be used.
Q14 · 2 Marks

Distinguish between induced EMF and induced current.

Answer: Induced EMF can be produced by changing magnetic flux even in an open circuit. Induced current requires a closed conducting path through which that EMF can drive charge.
Q15 · 2 Marks

Why does Lenz's law agree with the law of conservation of energy?

Answer: The induced effect opposes the change that produces it. External work is therefore required to maintain the change in many induction processes; the induced electrical energy comes from the supplied mechanical/electromagnetic energy rather than being created without input.
Q16 · 2 Marks

What happens to the induced EMF if the same change in magnetic flux occurs in half the time?

Answer: The magnitude of average induced EMF doubles because |εavg| = N|ΔΦ|/Δt.
Q17 · 2 Marks

Why can a changing current in one coil induce EMF in a nearby second coil even when there is no electrical connection between them?

Answer: The changing current changes the magnetic field and hence the magnetic flux linked with the second coil. Faraday's law then produces an induced EMF in that second coil.
Q18 · 2 Marks

State two factors on which the self-inductance of a long solenoid depends.

Answer: For L = μ0N²A/ℓ, it increases with N² and A and decreases with ℓ. For a more general solenoid, the magnetic permeability of the core also matters.

5. Numerical and Application Questions — 3 Marks

Q19 · 3 Marks

A 200-turn coil of area 0.020 m² is placed with its area vector parallel to a 0.50 T magnetic field. The field falls uniformly to 0.10 T in 0.40 s. Calculate the magnitude of the average induced EMF.

Solution:
Initial flux per turn = 0.50 × 0.020 = 0.010 Wb.
Final flux per turn = 0.10 × 0.020 = 0.002 Wb.
|ΔΦ| = 0.008 Wb.
|εavg| = N|ΔΦ|/Δt = 200 × 0.008/0.40 = 4.0 V.
Q20 · 3 Marks

A conducting rod of length 0.80 m moves at 5 m/s perpendicular to a uniform magnetic field of 0.30 T. Find the motional EMF. If the circuit resistance is 2 Ω, find the current assuming the simple closed-circuit model.

Solution:
ε = Bℓv = 0.30 × 0.80 × 5 = 1.20 V.
I = ε/R = 1.20/2 = 0.60 A.
Q21 · 3 Marks

An inductor of 2 H carries a current of 3 A. Calculate the energy stored in its magnetic field. What happens to the stored energy if the current is doubled?

Solution:
U = ½LI² = ½ × 2 × 3² = 9 J.
If current doubles, U ∝ I², so the energy becomes four times: 36 J.
Q22 · 3 Marks

The current in a 4 H inductor changes from 2 A to 5 A in 0.30 s. Find the magnitude of the average self-induced EMF.

Solution:
|εavg| = L|ΔI|/Δt = 4 × 3/0.30 = 40 V.
Q23 · 3 Marks

Two long coaxial solenoids have 500 and 1000 turns respectively, a common area of 4 × 10−3 m² and common length 0.50 m. Assuming an air core, calculate their mutual inductance.

Solution:
M = μ0N1N2A/ℓ
= (4π × 10−7)(500)(1000)(4 × 10−3)/0.50
≈ 5.03 × 10−3 H = 5.03 mH.
Q24 · 3 Marks

A 100-turn coil of area 0.010 m² is rotated in a 0.40 T field so that the angle between its area vector and the field changes from 0° to 90° in 0.20 s. Find the magnitude of the average induced EMF.

Solution:
Initial flux per turn = BA cos0° = 0.40 × 0.010 = 0.004 Wb.
Final flux per turn = BA cos90° = 0.
|εavg| = N|ΔΦ|/Δt = 100 × 0.004/0.20 = 2.0 V.

6. Higher-Order Questions — 3 to 5 Marks

Q25 · 3 Marks

A closed conducting loop has resistance 5 Ω. The magnetic flux linked with the loop changes from 0.08 Wb to 0.03 Wb. Find the total charge that passes through the loop.

Solution: |q| = |ΔΦ|/R = |0.03 − 0.08|/5 = 0.010 C.
Q26 · 3 Marks

A conducting loop is moved into a region of uniform magnetic field and then completely inside the field, where it remains stationary. During which stage is an induced EMF produced? Explain.

Answer: EMF is induced while the loop is entering the field because its magnetic flux is changing. Once the complete loop is stationary inside a uniform steady field, the flux is constant and the induced EMF becomes zero.
Q27 · 3 Marks

Explain briefly why eddy currents are produced in a bulk conductor placed in a changing magnetic field. State one useful application and one disadvantage.

Answer: Changing flux induces circulating currents within the conductor. Applications include electromagnetic braking and induction heating. They can also cause unwanted heating and energy loss, so laminated cores are used to reduce them. Treat this as enrichment rather than a separately named CBSE 2026–27 core item.
Q28 · 3 Marks

Two coils are close to each other. The current in the primary coil changes rapidly but the secondary coil is open. What is induced in the secondary coil, and what happens if the secondary circuit is then closed?

Answer: A changing primary current changes the flux linked with the secondary, producing an induced EMF across its open terminals. If the secondary is closed, that EMF drives an induced current.
Q29 · 3 Marks

Why is the induced EMF larger when the same change in flux occurs in a coil with more turns?

Answer: For an N-turn coil, |ε| = N|dΦ/dt|. Increasing N increases flux linkage and therefore increases the induced EMF for the same rate of flux change per turn.
Q30 · 3 Marks

Explain why the current in an ideal inductor cannot change instantaneously.

Answer: From ε = −L dI/dt, an instantaneous finite change in current would require an extremely large induced EMF. The induced EMF opposes sudden change, so an inductor resists abrupt changes in current.
Q31 · 3 Marks

Explain, using Faraday's law, why no induced EMF is produced when a coil moves in a uniform magnetic field without changing its area, orientation or linked flux.

Answer: Since B, A and θ remain unchanged, Φ = BA cosθ remains constant. Hence dΦ/dt = 0 and no induced EMF is produced by the unchanged flux linkage.
Q32 · 3 Marks

A coil has 400 turns and its linked magnetic flux changes by 2.0 × 10−3 Wb in 0.10 s. Find the magnitude of the average induced EMF.

Solution: |εavg| = N|ΔΦ|/Δt = 400 × 2.0 × 10−3/0.10 = 8.0 V.
Q33 · 3 Marks

State the difference between magnetic flux and flux linkage for a coil of N turns.

Answer: Magnetic flux Φ is the flux through one specified surface. If the same flux links each of N turns, total flux linkage is NΦ. Faraday's law uses the rate of change of flux linkage.
Q34 · 3 Marks

A 0.50 H inductor carries a current of 4 A. Find the energy stored. If the inductance becomes 2.0 H while current remains 4 A, find the new energy.

Solution: Initial U = ½LI² = 4 J. New U = ½ × 2.0 × 16 = 16 J.
Q35 · 3 Marks

A current in one coil changes at a rate of 20 A s−1. If the mutual inductance with a second coil is 0.15 H, calculate the magnitude of the induced EMF in the second coil.

Solution: |ε2| = M|dI1/dt| = 0.15 × 20 = 3.0 V.
Q36 · 3 Marks

Explain, using Faraday's law and Lenz's law, what happens when the north pole of a bar magnet is pushed towards a conducting coil.

Answer: The magnetic flux through the coil changes, so an EMF is induced. The induced current produces a magnetic field that opposes the increase in flux caused by the approaching north pole. Therefore the near face of the coil behaves so as to oppose the approach, consistent with Lenz's law.
Q37 · 3 Marks

A closed loop is placed in a magnetic field that changes with time. Explain why the induced current can change direction if the rate or direction of flux change changes.

Answer: The induced EMF is ε = −dΦ/dt. A reversal in dΦ/dt reverses the sign/direction of the induced EMF. In a closed loop, the induced current consequently reverses direction.
Q38 · 4 Marks

Derive the expression for the self-inductance of a long air-core solenoid having N turns, length ℓ and cross-sectional area A.

Solution:
For a long solenoid, B = μ0NI/ℓ.
Flux through each turn: Φ = BA = μ0NIA/ℓ.
Flux linkage: NΦ = μ0N²IA/ℓ.
Using NΦ = LI, we obtain L = μ0N²A/ℓ.
Q39 · 4 Marks

Explain mutual induction between two coils and obtain the expression for the mutual inductance of two long coaxial air-core solenoids with common length ℓ and area A.

Solution:
Current I1 in solenoid 1 produces B1 = μ0N1I1/ℓ.
Flux through each turn of solenoid 2: Φ2 = B1A.
Flux linkage with N2 turns = N2Φ2.
Thus N2Φ2 = μ0N1N2A I1/ℓ = MI1.
Therefore M = μ0N1N2A/ℓ.
Q40 · 5 Marks

Explain the principle of electromagnetic induction and discuss Faraday's laws, Lenz's law and the relation between induced EMF and magnetic flux for an N-turn coil.

Answer framework:
1. State electromagnetic induction: changing magnetic flux produces induced EMF.
2. State Faraday's first law.
3. State Faraday's second law and write ε = −N dΦ/dt.
4. Explain the negative sign through Lenz's law.
5. State that the induced effect opposes the change in flux that causes it, consistent with energy conservation.
Q41 · 5 Marks

Compare self-induction and mutual induction. Include the cause, induced EMF expression, coefficient, SI unit and one practical conceptual distinction.

Answer:
Self-induction: change of current in a coil induces EMF in the same coil; ε = −L dI/dt; coefficient is L.
Mutual induction: change of current in one coil induces EMF in another coupled coil; ε2 = −M dI1/dt; coefficient is M.
Both L and M have SI unit henry (H). Self-induction is a coil's response to change in its own current; mutual induction represents magnetic coupling between two circuits.

7. Assertion–Reason Practice

Q42 · 2 Marks

Assertion (A): A stationary magnet placed near a stationary coil does not produce a sustained induced current in the coil.
Reason (R): The magnetic flux linked with the coil remains constant if the magnetic configuration is unchanged.

Answer: Both A and R are true, and R correctly explains A.
Q43 · 2 Marks

Assertion (A): The induced current opposes the change in magnetic flux that produces it.
Reason (R): This is the content of Lenz's law and is consistent with conservation of energy.

Answer: Both A and R are true, and R correctly explains A.

8. High-Yield Practice Map

AreaTypical skillWhat you should be able to do
FluxApplicationChoose the correct angle and calculate/change Φ.
Faraday's lawConcept + numericalRelate induced EMF to rate of flux change.
Lenz's lawAnalysisDetermine induced-current direction from increasing/decreasing flux.
Motional EMFApplicationUse ε = Bℓv and determine direction.
Self-inductionConcept + numericalUse ε = −L dI/dt and L of a solenoid.
Energy in inductorNumericalUse U = ½LI² and proportional reasoning.
Mutual inductionConcept + numericalUse ε = −M dI/dt and ideal solenoid relations.
Long answersDerivation/reasoningPresent equations in logical sequence with definitions and units.

9. High-Yield Revision Checklist

✓ Define electromagnetic induction.

✓ Explain what magnetic flux is and identify the area-vector angle.

✓ State Faraday's laws and explain the minus sign.

✓ Apply Lenz's law to magnet-coil and changing-flux situations.

✓ Distinguish induced EMF from induced current.

✓ Solve standard motional-EMF problems.

✓ Define self-induction and self-inductance.

✓ Derive/use L = μ0N²A/ℓ for a long air-core solenoid.

✓ Use U = ½LI².

✓ Define mutual induction and mutual inductance.

✓ Derive/use M = μ0N1N2A/ℓ for ideal coaxial solenoids.

✓ Keep AC generator and transformer with Chapter 7 for current CBSE 2026–27 preparation.

10. Chapter 6 Resource Path

Start here: Electromagnetic Induction Class 12 Physics Notes

Next in the workflow: After this Important Questions page is published and verified, the next resource will be Chapter 6 MCQs, followed by Numericals, PYQs, Assertion–Reason, Case-Based Questions, Formula Sheet and Chapter Test.

The companion links will be added as each resource is actually published; no invented URLs are used.

11. Chapter 5 Connection

Chapter 5 explains magnetic fields and magnetic matter. Chapter 6 builds on that foundation by studying what happens when the magnetic flux linked with a circuit changes.

Magnetism and Matter Class 12 Physics Notes

Study + link audit note: The Chapter 6 Notes link on this page points to the published canonical Learn Revise Hub URL. No unpublished companion URL has been invented. Official CBSE links are retained for syllabus/SQP verification. These questions are original practice material; third-party “most important” lists are research inputs, not guaranteed predictions.

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